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Leetcode #1672: Richest Customer Wealth

In this guide, we solve Leetcode #1672 Richest Customer Wealth in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the i​​​​​​​​​​​th​​​​ customer has in the j​​​​​​​​​​​th​​​​ bank. Return the wealth that the richest customer has.

Quick Facts

  • Difficulty: Easy
  • Premium: No
  • Tags: Array, Matrix

Intuition

Grid problems are easiest when you define clear row/column boundaries.

A consistent traversal order prevents off-by-one errors.

Approach

Iterate by rows, columns, or layers depending on the requirement.

Keep bounds updated as the traversal progresses.

Steps:

  • Define bounds or directions.
  • Visit cells in order.
  • Update result and move bounds.

Example

Input: accounts = [[1,2,3],[3,2,1]] Output: 6 Explanation: 1st customer has wealth = 1 + 2 + 3 = 6 2nd customer has wealth = 3 + 2 + 1 = 6 Both customers are considered the richest with a wealth of 6 each, so return 6.

Python Solution

class Solution: def maximumWealth(self, accounts: List[List[int]]) -> int: return max(sum(v) for v in accounts)

Complexity

The time complexity is O(m×n)O(m \times n)O(m×n), where mmm and nnn are the number of rows and columns in the grid, respectively. The space complexity is O(1)O(1)O(1).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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