Shuffle String — LeetCode 1528 Python Solution
- Problem
- #1528
- Pattern
- Hash Map
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given a string s and an integer array indices of the same length. The string s will be shuffled such that the character at the ith position moves to indices[i] in the shuffled string.
Example
- Input
- s = "codeleet", indices = [4,5,6,7,0,2,1,3]
- Output
- "leetcode"
- Explanation
- As shown, "codeleet" becomes "leetcode" after shuffling.
Python solution
class Solution:
def restoreString(self, s: str, indices: List[int]) -> str:
ans = [None] * len(s)
for c, j in zip(s, indices):
ans[j] = c
return "".join(ans)Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n), where n is the length of the string auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1528. Shuffle String is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1528. Shuffle String?
- LeetCode 1528. Shuffle String is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1528. Shuffle String?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 1528. Shuffle String?
- The Python solution on this page uses O(n), where n is the length of the string auxiliary space.
- What topics does LeetCode 1528. Shuffle String cover?
- LeetCode 1528. Shuffle String is tagged Array and String on LeetCode.