Generate a String With Characters That Have Odd Counts — LeetCode 1374 Python Solution
- Problem
- #1374
- Pattern
- Hash Map
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times. The returned string must contain only lowercase English letters.
Example
- Input
- n = 4
- Output
- "pppz"
- Explanation
- "pppz" is a valid string since the character 'p' occurs three times and the character 'z' occurs once. Note that there are many other valid strings such as "ohhh" and "love".
Python solution
class Solution:
def generateTheString(self, n: int) -> str:
return 'a' * n if n & 1 else 'a' * (n - 1) + 'b'Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1374. Generate a String With Characters That Have Odd Counts is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1374. Generate a String With Characters That Have Odd Counts?
- LeetCode 1374. Generate a String With Characters That Have Odd Counts is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1374. Generate a String With Characters That Have Odd Counts?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 1374. Generate a String With Characters That Have Odd Counts?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 1374. Generate a String With Characters That Have Odd Counts cover?
- LeetCode 1374. Generate a String With Characters That Have Odd Counts is tagged String on LeetCode.