Increasing Decreasing String — LeetCode 1370 Python Solution

EasyHash TableStringCounting
Problem
#1370
Pattern
Hash Map
Reading time
2 min

The problem

You are given a string s. Reorder the string using the following algorithm: Remove the smallest character from s and append it to the result.

Example

Input
s = "aaaabbbbcccc"
Output
"abccbaabccba"
Explanation
After steps 1, 2 and 3 of the first iteration, result = "abc"

Python solution

Python
class Solution:
    def sortString(self, s: str) -> str:
        cnt = Counter(s)
        cs = ascii_lowercase + ascii_lowercase[::-1]
        ans = []
        while len(ans) < len(s):
            for c in cs:
                if cnt[c]:
                    ans.append(c)
                    cnt[c] -= 1
        return "".join(ans)

Complexity

MeasureComplexity
TimeO(n \times |\Sigma|)
SpaceO(|\Sigma|) auxiliary

Pattern: Hash Map

Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1370. Increasing Decreasing String is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Hash Table and Counting.

The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 1370. Increasing Decreasing String?
LeetCode 1370. Increasing Decreasing String is rated Easy on LeetCode.
What is the time complexity of LeetCode 1370. Increasing Decreasing String?
The Python solution on this page runs in O(n \times |\Sigma|).
What is the space complexity of LeetCode 1370. Increasing Decreasing String?
The Python solution on this page uses O(|\Sigma|) auxiliary space.
What topics does LeetCode 1370. Increasing Decreasing String cover?
LeetCode 1370. Increasing Decreasing String is tagged Hash Table, String and Counting on LeetCode.

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