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Leetcode #1315: Sum of Nodes with Even-Valued Grandparent

In this guide, we solve Leetcode #1315 Sum of Nodes with Even-Valued Grandparent in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

Given the root of a binary tree, return the sum of values of nodes with an even-valued grandparent. If there are no nodes with an even-valued grandparent, return 0.

Quick Facts

  • Difficulty: Medium
  • Premium: No
  • Tags: Tree, Depth-First Search, Breadth-First Search, Binary Tree

Intuition

We need to explore a structure deeply before backing up, which suits DFS.

DFS keeps local context on the call stack and is easy to implement recursively.

Approach

Define a recursive DFS that carries the necessary state.

Combine child results as the recursion unwinds.

Steps:

  • Define a recursive DFS with state.
  • Visit children and combine results.
  • Return the final aggregation.

Example

Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5] Output: 18 Explanation: The red nodes are the nodes with even-value grandparent while the blue nodes are the even-value grandparents.

Python Solution

# Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def sumEvenGrandparent(self, root: TreeNode) -> int: def dfs(root: TreeNode, x: int) -> int: if root is None: return 0 ans = dfs(root.left, root.val) + dfs(root.right, root.val) if x % 2 == 0: if root.left: ans += root.left.val if root.right: ans += root.right.val return ans return dfs(root, 1)

Complexity

The time complexity is O(n)O(n)O(n), and the space complexity is O(n)O(n)O(n). The space complexity is O(n)O(n)O(n).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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