Sum Root to Leaf Numbers — LeetCode 129 Python Solution
MediumTreeDepth-First SearchBinary Tree
- Problem
- #129
- Pattern
- Tree Traversal
- Reading time
- 3 min
- Source
- leetcode.com
The problem
You are given the root of a binary tree containing digits from 0 to 9 only. Each root-to-leaf path in the tree represents a number.
Example
- Input
- root = [1,2,3]
- Output
- 25
- Explanation
- The root-to-leaf path 1->2 represents the number 12.
Python solution
Python
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sumNumbers(self, root: Optional[TreeNode]) -> int:
def dfs(root, s):
if root is None:
return 0
s = s * 10 + root.val
if root.left is None and root.right is None:
return s
return dfs(root.left, s) + dfs(root.right, s)
return dfs(root, 0)Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(\log n) auxiliary |
Pattern: Tree Traversal
Choose the order — preorder, inorder, postorder, level — and the problem solves itself. LeetCode 129. Sum Root to Leaf Numbers is filed here because LeetCode tags it Tree and Binary Tree, which is the vocabulary this hub collects.
The tree traversal guide has the Python template for the pattern and the 225 LeetCode problems that use it.
Related problems
On a study list
This problem is on Top Interview 150.
Frequently asked questions
- How hard is LeetCode 129. Sum Root to Leaf Numbers?
- LeetCode 129. Sum Root to Leaf Numbers is rated Medium on LeetCode.
- What is the time complexity of LeetCode 129. Sum Root to Leaf Numbers?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 129. Sum Root to Leaf Numbers?
- The Python solution on this page uses O(\log n) auxiliary space.
- What topics does LeetCode 129. Sum Root to Leaf Numbers cover?
- LeetCode 129. Sum Root to Leaf Numbers is tagged Tree, Depth-First Search and Binary Tree on LeetCode.