Leetcode #1285: Find the Start and End Number of Continuous Ranges
In this guide, we solve Leetcode #1285 Find the Start and End Number of Continuous Ranges in Python and focus on the core idea that makes the solution efficient.
You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.
Problem Statement
Table: Logs +---------------+---------+ | Column Name | Type | +---------------+---------+ | log_id | int | +---------------+---------+ log_id is the column of unique values for this table. Each row of this table contains the ID in a log Table.
Quick Facts
- Difficulty: Medium
- Premium: Yes
- Tags: Database
Intuition
The task is relational in nature, which maps cleanly to DataFrame operations in Python.
By treating tables as DataFrames, joins and group-bys become concise and readable.
Approach
Load the inputs as DataFrames and apply the appropriate merge, filter, or group-by.
Select or rename the columns to match the required output.
Steps:
- Load inputs as DataFrames.
- Apply merge/groupby/filter operations.
- Select the output columns.
Example
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| log_id | int |
+---------------+---------+
log_id is the column of unique values for this table.
Each row of this table contains the ID in a log Table.
Python Solution
import duckdb
import pandas as pd
def solution(logs: pd.DataFrame) -> pd.DataFrame:
con = duckdb.connect()
con.register("Logs", logs)
return con.execute("""WITH
T AS (
SELECT
log_id,
SUM(delta) OVER (ORDER BY log_id) AS pid
FROM
(
SELECT
log_id,
IF((log_id - LAG(log_id) OVER (ORDER BY log_id)) = 1, 0, 1) AS delta
FROM Logs
) AS t
)
SELECT MIN(log_id) AS start_id, MAX(log_id) AS end_id
FROM T
GROUP BY pid;""").df()
Complexity
The time complexity is O(n log n) (typical). The space complexity is O(n).
Edge Cases and Pitfalls
Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.
Summary
This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.