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Leetcode #1247: Minimum Swaps to Make Strings Equal

In this guide, we solve Leetcode #1247 Minimum Swaps to Make Strings Equal in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given two strings s1 and s2 of equal length consisting of letters "x" and "y" only. Your task is to make these two strings equal to each other.

Quick Facts

  • Difficulty: Medium
  • Premium: No
  • Tags: Greedy, Math, String

Intuition

A locally optimal choice leads to a globally optimal result for this structure.

That means we can commit to decisions as we scan without backtracking.

Approach

Sort or preprocess if needed, then repeatedly take the best available local choice.

Maintain the minimal state necessary to validate the greedy decision.

Steps:

  • Sort or preprocess as needed.
  • Iterate and pick the best local option.
  • Track the current solution.

Example

Input: s1 = "xx", s2 = "yy" Output: 1 Explanation: Swap s1[0] and s2[1], s1 = "yx", s2 = "yx".

Python Solution

class Solution: def minimumSwap(self, s1: str, s2: str) -> int: xy = yx = 0 for a, b in zip(s1, s2): xy += a < b yx += a > b if (xy + yx) % 2: return -1 return xy // 2 + yx // 2 + xy % 2 + yx % 2

Complexity

The time complexity is O(n)O(n)O(n), where nnn is the length of the strings s1s_1s1​ and s2s_2s2​. The space complexity is O(1)O(1)O(1).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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