Last Substring in Lexicographical Order — LeetCode 1163 Python Solution
HardTwo PointersString
- Problem
- #1163
- Pattern
- Two Pointers
- Reading time
- 3 min
- Source
- leetcode.com
The problem
Given a string s, return the last substring of s in lexicographical order.
Example
- Input
- s = "abab"
- Output
- "bab"
- Explanation
- The substrings are ["a", "ab", "aba", "abab", "b", "ba", "bab"]. The lexicographically maximum substring is "bab".
Python solution
Python
class Solution:
def lastSubstring(self, s: str) -> str:
i, j, k = 0, 1, 0
while j + k < len(s):
if s[i + k] == s[j + k]:
k += 1
elif s[i + k] < s[j + k]:
i += k + 1
k = 0
if i >= j:
j = i + 1
else:
j += k + 1
k = 0
return s[i:]Complexity
| Measure | Complexity |
|---|---|
| Time | O(n), where n is the length of string s |
| Space | O(1) auxiliary |
Pattern: Two Pointers
Use the order already in the input to discard half the search space at every step. LeetCode 1163. Last Substring in Lexicographical Order is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Two Pointers.
The two pointers guide has the Python template for the pattern and the 201 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1163. Last Substring in Lexicographical Order?
- LeetCode 1163. Last Substring in Lexicographical Order is rated Hard on LeetCode.
- What is the time complexity of LeetCode 1163. Last Substring in Lexicographical Order?
- The Python solution on this page runs in O(n), where n is the length of string s.
- What is the space complexity of LeetCode 1163. Last Substring in Lexicographical Order?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 1163. Last Substring in Lexicographical Order cover?
- LeetCode 1163. Last Substring in Lexicographical Order is tagged Two Pointers and String on LeetCode.