Find Words That Can Be Formed by Characters — LeetCode 1160 Python Solution
- Problem
- #1160
- Pattern
- Hash Map
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given an array of strings words and a string chars. A string is good if it can be formed by characters from chars (each character can only be used once for each word in words).
Example
- Input
- words = ["cat","bt","hat","tree"], chars = "atach"
- Output
- 6
- Explanation
- The strings that can be formed are "cat" and "hat" so the answer is 3 + 3 = 6.
Python solution
class Solution:
def countCharacters(self, words: List[str], chars: str) -> int:
cnt = Counter(chars)
ans = 0
for w in words:
wc = Counter(w)
if all(cnt[c] >= v for c, v in wc.items()):
ans += len(w)
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(L) |
| Space | O(C) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1160. Find Words That Can Be Formed by Characters is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Hash Table and Counting.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1160. Find Words That Can Be Formed by Characters?
- LeetCode 1160. Find Words That Can Be Formed by Characters is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1160. Find Words That Can Be Formed by Characters?
- The Python solution on this page runs in O(L).
- What is the space complexity of LeetCode 1160. Find Words That Can Be Formed by Characters?
- The Python solution on this page uses O(C) auxiliary space.
- What topics does LeetCode 1160. Find Words That Can Be Formed by Characters cover?
- LeetCode 1160. Find Words That Can Be Formed by Characters is tagged Array, Hash Table, String and Counting on LeetCode.