Distinct Subsequences — LeetCode 115 Python Solution
- Problem
- #115
- Pattern
- Dynamic Programming
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given two strings s and t, return the number of distinct subsequences of s which equals t. The test cases are generated so that the answer fits on a 32-bit signed integer.
Example
- Input
- s = "rabbbit", t = "rabbit"
- Output
- 3
- Explanation
- As shown below, there are 3 ways you can generate "rabbit" from s.
Python solution
class Solution:
def numDistinct(self, s: str, t: str) -> int:
m, n = len(s), len(t)
f = [[0] * (n + 1) for _ in range(m + 1)]
for i in range(m + 1):
f[i][0] = 1
for i, a in enumerate(s, 1):
for j, b in enumerate(t, 1):
f[i][j] = f[i - 1][j]
if a == b:
f[i][j] += f[i - 1][j - 1]
return f[m][n]Complexity
| Measure | Complexity |
|---|---|
| Time | O(m \times n) |
| Space | O(m \times n) auxiliary |
Pattern: Dynamic Programming
Define a state, write the transition, and stop recomputing the same subproblem. LeetCode 115. Distinct Subsequences is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Dynamic Programming.
The dynamic programming guide has the Python template for the pattern and the 481 LeetCode problems that use it.
Related problems
On a study list
This problem is on NeetCode 150.
Frequently asked questions
- How hard is LeetCode 115. Distinct Subsequences?
- LeetCode 115. Distinct Subsequences is rated Hard on LeetCode.
- What is the time complexity of LeetCode 115. Distinct Subsequences?
- The Python solution on this page runs in O(m \times n).
- What is the space complexity of LeetCode 115. Distinct Subsequences?
- The Python solution on this page uses O(m \times n) auxiliary space.
- What topics does LeetCode 115. Distinct Subsequences cover?
- LeetCode 115. Distinct Subsequences is tagged String and Dynamic Programming on LeetCode.