Alphabet Board Path — LeetCode 1138 Python Solution
- Problem
- #1138
- Pattern
- Hash Map
- Reading time
- 4 min
- Source
- leetcode.com
The problem
On an alphabet board, we start at position (0, 0), corresponding to character board[0][0]. Here, board = ["abcde", "fghij", "klmno", "pqrst", "uvwxy", "z"], as shown in the diagram below.
Example
- Input
- target = "leet"
- Output
- "DDR!UURRR!!DDD!"
Python solution
class Solution:
def alphabetBoardPath(self, target: str) -> str:
i = j = 0
ans = []
for c in target:
v = ord(c) - ord("a")
x, y = v // 5, v % 5
while j > y:
j -= 1
ans.append("L")
while i > x:
i -= 1
ans.append("U")
while j < y:
j += 1
ans.append("R")
while i < x:
i += 1
ans.append("D")
ans.append("!")
return "".join(ans)Complexity
| Measure | Complexity |
|---|---|
| Time | O(n), where n is the length of the string target, as each character in the string target needs to be traversed |
| Space | O(1) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1138. Alphabet Board Path is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Hash Table.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1138. Alphabet Board Path?
- LeetCode 1138. Alphabet Board Path is rated Medium on LeetCode.
- What is the time complexity of LeetCode 1138. Alphabet Board Path?
- The Python solution on this page runs in O(n), where n is the length of the string target, as each character in the string target needs to be traversed.
- What is the space complexity of LeetCode 1138. Alphabet Board Path?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 1138. Alphabet Board Path cover?
- LeetCode 1138. Alphabet Board Path is tagged Hash Table and String on LeetCode.