Parsing A Boolean Expression — LeetCode 1106 Python Solution
HardStackRecursionString
- Problem
- #1106
- Pattern
- Stack
- Reading time
- 4 min
- Source
- leetcode.com
The problem
A boolean expression is an expression that evaluates to either true or false. It can be in one of the following shapes: 't' that evaluates to true.
Example
- Input
- expression = "&(|(f))"
- Output
- false
- Explanation
- First, evaluate |(f) --> f. The expression is now "&(f)".
Python solution
Python
class Solution:
def parseBoolExpr(self, expression: str) -> bool:
stk = []
for c in expression:
if c in 'tf!&|':
stk.append(c)
elif c == ')':
t = f = 0
while stk[-1] in 'tf':
t += stk[-1] == 't'
f += stk[-1] == 'f'
stk.pop()
match stk.pop():
case '!':
c = 't' if f else 'f'
case '&':
c = 'f' if f else 't'
case '|':
c = 't' if t else 'f'
stk.append(c)
return stk[0] == 't'Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n) auxiliary |
Pattern: Stack
When the most recent unresolved thing is the one that matters, use a stack. LeetCode 1106. Parsing A Boolean Expression is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Stack.
The stack guide has the Python template for the pattern and the 194 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1106. Parsing A Boolean Expression?
- LeetCode 1106. Parsing A Boolean Expression is rated Hard on LeetCode.
- What is the time complexity of LeetCode 1106. Parsing A Boolean Expression?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 1106. Parsing A Boolean Expression?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 1106. Parsing A Boolean Expression cover?
- LeetCode 1106. Parsing A Boolean Expression is tagged Stack, Recursion and String on LeetCode.