Remove All Adjacent Duplicates In String — LeetCode 1047 Python Solution
EasyStackString
- Problem
- #1047
- Pattern
- Stack
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given a string s consisting of lowercase English letters. A duplicate removal consists of choosing two adjacent and equal letters and removing them.
Example
- Input
- s = "abbaca"
- Output
- "ca"
- Explanation
- For example, in "abbaca" we could remove "bb" since the letters are adjacent and equal, and this is the only possible move. The result of this move is that the string is "aaca", of which only "aa" is possible, so the final string is "ca".
Python solution
Python
class Solution:
def removeDuplicates(self, s: str) -> str:
stk = []
for c in s:
if stk and stk[-1] == c:
stk.pop()
else:
stk.append(c)
return ''.join(stk)Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n) auxiliary |
Pattern: Stack
When the most recent unresolved thing is the one that matters, use a stack. LeetCode 1047. Remove All Adjacent Duplicates In String is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Stack.
The stack guide has the Python template for the pattern and the 194 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1047. Remove All Adjacent Duplicates In String?
- LeetCode 1047. Remove All Adjacent Duplicates In String is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1047. Remove All Adjacent Duplicates In String?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 1047. Remove All Adjacent Duplicates In String?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 1047. Remove All Adjacent Duplicates In String cover?
- LeetCode 1047. Remove All Adjacent Duplicates In String is tagged Stack and String on LeetCode.