Find Common Characters — LeetCode 1002 Python Solution
- Problem
- #1002
- Pattern
- Hash Map
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given a string array words, return an array of all characters that show up in all strings within the words (including duplicates). You may return the answer in any order.
Example
- Input
- words = ["bella","label","roller"]
- Output
- ["e","l","l"]
Python solution
class Solution:
def commonChars(self, words: List[str]) -> List[str]:
cnt = Counter(words[0])
for w in words:
t = Counter(w)
for c in cnt:
cnt[c] = min(cnt[c], t[c])
return list(cnt.elements())Complexity
| Measure | Complexity |
|---|---|
| Time | O(n \sum w_i) |
| Space | O(|\Sigma|) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1002. Find Common Characters is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Hash Table.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
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Frequently asked questions
- How hard is LeetCode 1002. Find Common Characters?
- LeetCode 1002. Find Common Characters is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1002. Find Common Characters?
- The Python solution on this page runs in O(n \sum w_i).
- What is the space complexity of LeetCode 1002. Find Common Characters?
- The Python solution on this page uses O(|\Sigma|) auxiliary space.
- What topics does LeetCode 1002. Find Common Characters cover?
- LeetCode 1002. Find Common Characters is tagged Array, Hash Table and String on LeetCode.