Remove Duplicates from Sorted List II — LeetCode 82 Python Solution
- Problem
- #82
- Pattern
- Linked List
- Reading time
- 3 min
- Source
- leetcode.com
The problem
Given the head of a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. Return the linked list sorted as well.
Example
- Input
- head = [1,2,3,3,4,4,5]
- Output
- [1,2,5]
Python solution
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def deleteDuplicates(self, head: Optional[ListNode]) -> Optional[ListNode]:
dummy = pre = ListNode(next=head)
cur = head
while cur:
while cur.next and cur.next.val == cur.val:
cur = cur.next
if pre.next == cur:
pre = cur
else:
pre.next = cur.next
cur = cur.next
return dummy.nextComplexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(1) auxiliary |
Pattern: Linked List
Rewire pointers in place, with a dummy head and a saved next to keep it safe. LeetCode 82. Remove Duplicates from Sorted List II is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Linked List.
The linked list guide has the Python template for the pattern and the 75 LeetCode problems that use it.
Related problems
On a study list
This problem is on Top Interview 150.
Frequently asked questions
- How hard is LeetCode 82. Remove Duplicates from Sorted List II?
- LeetCode 82. Remove Duplicates from Sorted List II is rated Medium on LeetCode.
- What is the time complexity of LeetCode 82. Remove Duplicates from Sorted List II?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 82. Remove Duplicates from Sorted List II?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 82. Remove Duplicates from Sorted List II cover?
- LeetCode 82. Remove Duplicates from Sorted List II is tagged Linked List and Two Pointers on LeetCode.