Random Pick with Blacklist — LeetCode 710 Python Solution
HardArrayHash TableMathBinary SearchSortingRandomized
- Problem
- #710
- Pattern
- Binary Search
- Reading time
- 4 min
- Source
- leetcode.com
The problem
You are given an integer n and an array of unique integers blacklist. Design an algorithm to pick a random integer in the range [0, n - 1] that is not in blacklist.
Example
- Input
- ["Solution", "pick", "pick", "pick", "pick", "pick", "pick", "pick"]
- Output
- [null, 0, 4, 1, 6, 1, 0, 4]
- Explanation
- Solution solution = new Solution(7, [2, 3, 5]);
Python solution
Python
class Solution:
def __init__(self, n: int, blacklist: List[int]):
self.k = n - len(blacklist)
self.d = {}
i = self.k
black = set(blacklist)
for b in blacklist:
if b < self.k:
while i in black:
i += 1
self.d[b] = i
i += 1
def pick(self) -> int:
x = randrange(self.k)
return self.d.get(x, x)
# Your Solution object will be instantiated and called as such:
# obj = Solution(n, blacklist)
# param_1 = obj.pick()Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n) auxiliary |
Pattern: Binary Search
Halve the search space each step — over an array, or over the answer itself. LeetCode 710. Random Pick with Blacklist is filed here because LeetCode tags it Binary Search, which is the vocabulary this hub collects.
The binary search guide has the Python template for the pattern and the 254 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 710. Random Pick with Blacklist?
- LeetCode 710. Random Pick with Blacklist is rated Hard on LeetCode.
- What is the time complexity of LeetCode 710. Random Pick with Blacklist?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 710. Random Pick with Blacklist?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 710. Random Pick with Blacklist cover?
- LeetCode 710. Random Pick with Blacklist is tagged Array, Hash Table, Math, Binary Search, Sorting and Randomized on LeetCode.