Maximum Swap — LeetCode 670 Python Solution

MediumGreedyMath
Problem
#670
Pattern
Greedy
Reading time
2 min

The problem

You are given an integer num. You can swap two digits at most once to get the maximum valued number.

Example

Input
num = 2736
Output
7236
Explanation
Swap the number 2 and the number 7.

Python solution

Python
class Solution:
    def maximumSwap(self, num: int) -> int:
        s = list(str(num))
        n = len(s)
        d = list(range(n))
        for i in range(n - 2, -1, -1):
            if s[i] <= s[d[i + 1]]:
                d[i] = d[i + 1]
        for i, j in enumerate(d):
            if s[i] < s[j]:
                s[i], s[j] = s[j], s[i]
                break
        return int(''.join(s))

Complexity

MeasureComplexity
TimeO(\log M)
SpaceO(\log M) auxiliary

Pattern: Greedy

Take the locally best option every time — when you can prove that never costs you later. LeetCode 670. Maximum Swap is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Greedy.

The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 670. Maximum Swap?
LeetCode 670. Maximum Swap is rated Medium on LeetCode.
What is the time complexity of LeetCode 670. Maximum Swap?
The Python solution on this page runs in O(\log M).
What is the space complexity of LeetCode 670. Maximum Swap?
The Python solution on this page uses O(\log M) auxiliary space.
What topics does LeetCode 670. Maximum Swap cover?
LeetCode 670. Maximum Swap is tagged Greedy and Math on LeetCode.

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