Rotate List — LeetCode 61 Python Solution
MediumLinked ListTwo Pointers
- Problem
- #61
- Pattern
- Linked List
- Reading time
- 4 min
- Source
- leetcode.com
The problem
Given the head of a linked list, rotate the list to the right by k places.
Example
- Input
- head = [1,2,3,4,5], k = 2
- Output
- [4,5,1,2,3]
Python solution
Python
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def rotateRight(self, head: Optional[ListNode], k: int) -> Optional[ListNode]:
if head is None or head.next is None:
return head
cur, n = head, 0
while cur:
n += 1
cur = cur.next
k %= n
if k == 0:
return head
fast = slow = head
for _ in range(k):
fast = fast.next
while fast.next:
fast, slow = fast.next, slow.next
ans = slow.next
slow.next = None
fast.next = head
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n), where n is the number of nodes in the linked list |
| Space | O(1) auxiliary |
Pattern: Linked List
Rewire pointers in place, with a dummy head and a saved next to keep it safe. LeetCode 61. Rotate List is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Linked List.
The linked list guide has the Python template for the pattern and the 75 LeetCode problems that use it.
Related problems
On a study list
This problem is on Top Interview 150.
Frequently asked questions
- How hard is LeetCode 61. Rotate List?
- LeetCode 61. Rotate List is rated Medium on LeetCode.
- What is the time complexity of LeetCode 61. Rotate List?
- The Python solution on this page runs in O(n), where n is the number of nodes in the linked list.
- What is the space complexity of LeetCode 61. Rotate List?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 61. Rotate List cover?
- LeetCode 61. Rotate List is tagged Linked List and Two Pointers on LeetCode.