License Key Formatting — LeetCode 482 Python Solution
- Problem
- #482
- Pattern
- Hash Map
- Reading time
- 3 min
- Source
- leetcode.com
The problem
You are given a license key represented as a string s that consists of only alphanumeric characters and dashes. The string is separated into n + 1 groups by n dashes.
Example
- Input
- s = "5F3Z-2e-9-w", k = 4
- Output
- "5F3Z-2E9W"
- Explanation
- The string s has been split into two parts, each part has 4 characters.
Python solution
class Solution:
def licenseKeyFormatting(self, s: str, k: int) -> str:
n = len(s)
cnt = (n - s.count("-")) % k or k
ans = []
for i, c in enumerate(s):
if c == "-":
continue
ans.append(c.upper())
cnt -= 1
if cnt == 0:
cnt = k
if i != n - 1:
ans.append("-")
return "".join(ans).rstrip("-")Complexity
| Measure | Complexity |
|---|---|
| Time | O(n), where n is the length of the string s |
| Space | O(1) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 482. License Key Formatting is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 482. License Key Formatting?
- LeetCode 482. License Key Formatting is rated Easy on LeetCode.
- What is the time complexity of LeetCode 482. License Key Formatting?
- The Python solution on this page runs in O(n), where n is the length of the string s.
- What is the space complexity of LeetCode 482. License Key Formatting?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 482. License Key Formatting cover?
- LeetCode 482. License Key Formatting is tagged String on LeetCode.