Permutations — LeetCode 46 Python Solution
- Problem
- #46
- Pattern
- Backtracking
- Reading time
- 3 min
- Source
- leetcode.com
The problem
Given an array nums of distinct integers, return all the possible permutations. You can return the answer in any order.
Example
- Input
- nums = [1,2,3]
- Output
- [[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
Python solution
class Solution:
def permute(self, nums: List[int]) -> List[List[int]]:
def dfs(i: int):
if i >= n:
ans.append(t[:])
return
for j, x in enumerate(nums):
if not vis[j]:
vis[j] = True
t[i] = x
dfs(i + 1)
vis[j] = False
n = len(nums)
vis = [False] * n
t = [0] * n
ans = []
dfs(0)
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n \times n!), where n is the length of the array |
| Space | O(depth) auxiliary |
Pattern: Backtracking
Build candidates one choice at a time and abandon a branch the moment it cannot work. LeetCode 46. Permutations is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Backtracking.
The backtracking guide has the Python template for the pattern and the 105 LeetCode problems that use it.
Related problems
On study lists
This problem is on NeetCode 150, Grind 75 and Top Interview 150.
Frequently asked questions
- How hard is LeetCode 46. Permutations?
- LeetCode 46. Permutations is rated Medium on LeetCode.
- What is the time complexity of LeetCode 46. Permutations?
- The Python solution on this page runs in O(n \times n!), where n is the length of the array.
- What is the space complexity of LeetCode 46. Permutations?
- The Python solution on this page uses O(depth) auxiliary space.
- What topics does LeetCode 46. Permutations cover?
- LeetCode 46. Permutations is tagged Array and Backtracking on LeetCode.