Find All Duplicates in an Array — LeetCode 442 Python Solution
- Problem
- #442
- Pattern
- Sorting
- Reading time
- 2 min
- Source
- leetcode.com
The problem
Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that appears twice. You must write an algorithm that runs in O(n) time and uses only constant auxiliary space, excluding the space needed to store the output
This statement is abridged. Read the full problem on LeetCode.
Example
- Input
- nums = [4,3,2,7,8,2,3,1]
- Output
- [2,3]
Python solution
class Solution:
def findDuplicates(self, nums: List[int]) -> List[int]:
for i in range(len(nums)):
while nums[i] != nums[nums[i] - 1]:
nums[nums[i] - 1], nums[i] = nums[i], nums[nums[i] - 1]
return [v for i, v in enumerate(nums) if v != i + 1]Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n) auxiliary |
Pattern: Sorting
Spend O(n log n) once to buy an ordering that makes the rest of the problem trivial. LeetCode 442. Find All Duplicates in an Array is filed here because LeetCode tags it Sorting, which is the vocabulary this hub collects.
The sorting guide has the Python template for the pattern and the 401 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 442. Find All Duplicates in an Array?
- LeetCode 442. Find All Duplicates in an Array is rated Medium on LeetCode.
- What is the time complexity of LeetCode 442. Find All Duplicates in an Array?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 442. Find All Duplicates in an Array?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 442. Find All Duplicates in an Array cover?
- LeetCode 442. Find All Duplicates in an Array is tagged Array, Hash Table and Sorting on LeetCode.