How hard is LeetCode 3000. Maximum Area of Longest Diagonal Rectangle?

LeetCode 3000. Maximum Area of Longest Diagonal Rectangle is rated Easy on LeetCode.

What is the time complexity of LeetCode 3000. Maximum Area of Longest Diagonal Rectangle?

The Python solution on this page runs in O(n), where n is the number of rectangles.

What is the space complexity of LeetCode 3000. Maximum Area of Longest Diagonal Rectangle?

The Python solution on this page uses O(1) auxiliary space.

What topics does LeetCode 3000. Maximum Area of Longest Diagonal Rectangle cover?

LeetCode 3000. Maximum Area of Longest Diagonal Rectangle is tagged Array on LeetCode.

EasyNo. 3000

Maximum Area of Longest Diagonal Rectangle — LeetCode 3000 Python Solution

Topics: Array
Reading time: 2 min
Source: leetcode.com

The problem

You are given a 2D 0-indexed integer array dimensions. For all indices i, 0 <= i < dimensions.length, dimensions[i][0] represents the length and dimensions[i][1] represents the width of the rectangle i.

Example

Input: dimensions = [[9,3],[8,6]]
Output: 48
Explanation: For index = 0, length = 9 and width = 3. Diagonal length = sqrt(9 * 9 + 3 * 3) = sqrt(90) ≈ 9.487.

Python solution

PythonSolution

class Solution:
    def areaOfMaxDiagonal(self, dimensions: List[List[int]]) -> int:
        ans = mx = 0
        for l, w in dimensions:
            t = l**2 + w**2
            if mx < t:
                mx = t
                ans = l * w
            elif mx == t:
                ans = max(ans, l * w)
        return ans

Complexity

Time: O(n)where n is the number of rectangles
Space · auxiliary: O(1)

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0699	Falling Squares	Hard

Frequently asked questions

How hard is LeetCode 3000. Maximum Area of Longest Diagonal Rectangle?: LeetCode 3000. Maximum Area of Longest Diagonal Rectangle is rated Easy on LeetCode.
What is the time complexity of LeetCode 3000. Maximum Area of Longest Diagonal Rectangle?: The Python solution on this page runs in O(n), where n is the number of rectangles.
What is the space complexity of LeetCode 3000. Maximum Area of Longest Diagonal Rectangle?: The Python solution on this page uses O(1) auxiliary space.
What topics does LeetCode 3000. Maximum Area of Longest Diagonal Rectangle cover?: LeetCode 3000. Maximum Area of Longest Diagonal Rectangle is tagged Array on LeetCode.

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python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

Technical interview · 45 minsolution.pyShared editor · Python 3Longest substring without repeatsMediumGiven a string s, return the length of the longest contiguous substring in which every character is unique.s = "abcabcbb"
→ 31def length_of_longest_substring(s: str) -> int:2 last_seen = {}3 left = best = 04 for right, ch in enumerate(s):5 if ch in last_seen and last_seen[ch] >= left:

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

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Transcribing...

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python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

Primary display

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

The problem

Example

Python solution

Complexity

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