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Leetcode #2908: Minimum Sum of Mountain Triplets I

In this guide, we solve Leetcode #2908 Minimum Sum of Mountain Triplets I in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given a 0-indexed array nums of integers. A triplet of indices (i, j, k) is a mountain if: i < j < k nums[i] < nums[j] and nums[k] < nums[j] Return the minimum possible sum of a mountain triplet of nums.

Quick Facts

  • Difficulty: Easy
  • Premium: No
  • Tags: Array

Intuition

The constraints allow a direct scan that keeps only the essential state.

By translating the requirements into a clean loop, the logic stays easy to reason about.

Approach

Iterate through the data once, updating the state needed to compute the answer.

Return the final state after the traversal is complete.

Steps:

  • Parse the input.
  • Iterate and update state.
  • Return the computed answer.

Example

Input: nums = [8,6,1,5,3] Output: 9 Explanation: Triplet (2, 3, 4) is a mountain triplet of sum 9 since: - 2 < 3 < 4 - nums[2] < nums[3] and nums[4] < nums[3] And the sum of this triplet is nums[2] + nums[3] + nums[4] = 9. It can be shown that there are no mountain triplets with a sum of less than 9.

Python Solution

class Solution: def minimumSum(self, nums: List[int]) -> int: n = len(nums) right = [inf] * (n + 1) for i in range(n - 1, -1, -1): right[i] = min(right[i + 1], nums[i]) ans = left = inf for i, x in enumerate(nums): if left < x and right[i + 1] < x: ans = min(ans, left + x + right[i + 1]) left = min(left, x) return -1 if ans == inf else ans

Complexity

The time complexity is O(n)O(n)O(n), and the space complexity is O(n)O(n)O(n). The space complexity is O(n)O(n)O(n).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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