Stealth Interview
  • Features
  • Pricing
  • Blog
  • Login
  • Sign up

Leetcode #2802: Find The K-th Lucky Number

In this guide, we solve Leetcode #2802 Find The K-th Lucky Number in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

We know that 4 and 7 are lucky digits. Also, a number is called lucky if it contains only lucky digits.

Quick Facts

  • Difficulty: Medium
  • Premium: Yes
  • Tags: Bit Manipulation, Math, String

Intuition

The problem structure lets us track state with bitwise operations.

Bit operations are constant time and avoid extra memory.

Approach

Apply XOR/AND/OR and shifts to maintain the required invariant.

Aggregate the result in a single pass.

Steps:

  • Identify a bitwise invariant.
  • Combine values with bit operations.
  • Return the aggregated result.

Example

Input: k = 4 Output: "47" Explanation: The first lucky number is 4, the second one is 7, the third one is 44 and the fourth one is 47.

Python Solution

class Solution: def kthLuckyNumber(self, k: int) -> str: n = 1 while k > 1 << n: k -= 1 << n n += 1 ans = [] while n: n -= 1 if k <= 1 << n: ans.append("4") else: ans.append("7") k -= 1 << n return "".join(ans)

Complexity

The time complexity is O(log⁡k)O(\log k)O(logk), and the space complexity is O(log⁡k)O(\log k)O(logk). The space complexity is O(log⁡k)O(\log k)O(logk).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


Ace your next coding interview

We're here to help you ace your next coding interview.

Subscribe
Stealth Interview
© 2026 Stealth Interview®Stealth Interview is a registered trademark. All rights reserved.
Product
  • Blog
  • Pricing
Company
  • Terms of Service
  • Privacy Policy