How hard is LeetCode 2717. Semi-Ordered Permutation?

LeetCode 2717. Semi-Ordered Permutation is rated Easy on LeetCode.

What is the time complexity of LeetCode 2717. Semi-Ordered Permutation?

The Python solution on this page runs in O(n), where n is the length of the array.

What is the space complexity of LeetCode 2717. Semi-Ordered Permutation?

The Python solution on this page uses O(1) auxiliary space.

What topics does LeetCode 2717. Semi-Ordered Permutation cover?

LeetCode 2717. Semi-Ordered Permutation is tagged Array and Simulation on LeetCode.

EasyNo. 2717

Semi-Ordered Permutation — LeetCode 2717 Python Solution

Topics: Array, Simulation
Reading time: 2 min
Source: leetcode.com

The problem

You are given a 0-indexed permutation of n integers nums. A permutation is called semi-ordered if the first number equals 1 and the last number equals n.

Example

Input: nums = [2,1,4,3]
Output: 2
Explanation: We can make the permutation semi-ordered using these sequence of operations:

Python solution

PythonSolution

class Solution:
    def semiOrderedPermutation(self, nums: List[int]) -> int:
        n = len(nums)
        i = nums.index(1)
        j = nums.index(n)
        k = 1 if i < j else 2
        return i + n - j - k

Complexity

Time: O(n)where n is the length of the array
Space · auxiliary: O(1)

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Frequently asked questions

How hard is LeetCode 2717. Semi-Ordered Permutation?: LeetCode 2717. Semi-Ordered Permutation is rated Easy on LeetCode.
What is the time complexity of LeetCode 2717. Semi-Ordered Permutation?: The Python solution on this page runs in O(n), where n is the length of the array.
What is the space complexity of LeetCode 2717. Semi-Ordered Permutation?: The Python solution on this page uses O(1) auxiliary space.
What topics does LeetCode 2717. Semi-Ordered Permutation cover?: LeetCode 2717. Semi-Ordered Permutation is tagged Array and Simulation on LeetCode.

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python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

Technical interview · 45 minsolution.pyShared editor · Python 3Longest substring without repeatsMediumGiven a string s, return the length of the longest contiguous substring in which every character is unique.s = "abcabcbb"
→ 31def length_of_longest_substring(s: str) -> int:2 last_seen = {}3 left = best = 04 for right, ch in enumerate(s):5 if ch in last_seen and last_seen[ch] >= left:

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

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python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

Primary display

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

The problem

Example

Python solution

Complexity

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