Minimum Operations to Make Array Equal II — LeetCode 2541 Python Solution
- Problem
- #2541
- Pattern
- Greedy
- Reading time
- 3 min
- Source
- leetcode.com
The problem
You are given two integer arrays nums1 and nums2 of equal length n and an integer k. You can perform the following operation on nums1: Choose two indexes i and j and increment nums1[i] by k and decrement nums1[j] by k.
Example
- Input
- nums1 = [4,3,1,4], nums2 = [1,3,7,1], k = 3
- Output
- 2
- Explanation
- In 2 operations, we can transform nums1 to nums2.
Python solution
class Solution:
def minOperations(self, nums1: List[int], nums2: List[int], k: int) -> int:
ans = x = 0
for a, b in zip(nums1, nums2):
if k == 0:
if a != b:
return -1
continue
if (a - b) % k:
return -1
y = (a - b) // k
ans += abs(y)
x += y
return -1 if x else ans // 2Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(1), where n is the length of the array auxiliary |
Pattern: Greedy
Take the locally best option every time — when you can prove that never costs you later. LeetCode 2541. Minimum Operations to Make Array Equal II is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Greedy.
The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 2541. Minimum Operations to Make Array Equal II?
- LeetCode 2541. Minimum Operations to Make Array Equal II is rated Medium on LeetCode.
- What is the time complexity of LeetCode 2541. Minimum Operations to Make Array Equal II?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 2541. Minimum Operations to Make Array Equal II?
- The Python solution on this page uses O(1), where n is the length of the array auxiliary space.
- What topics does LeetCode 2541. Minimum Operations to Make Array Equal II cover?
- LeetCode 2541. Minimum Operations to Make Array Equal II is tagged Greedy, Array and Math on LeetCode.