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Leetcode #2432: The Employee That Worked on the Longest Task

In this guide, we solve Leetcode #2432 The Employee That Worked on the Longest Task in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

There are n employees, each with a unique id from 0 to n - 1. You are given a 2D integer array logs where logs[i] = [idi, leaveTimei] where: idi is the id of the employee that worked on the ith task, and leaveTimei is the time at which the employee finished the ith task.

Quick Facts

  • Difficulty: Easy
  • Premium: No
  • Tags: Array

Intuition

The constraints allow a direct scan that keeps only the essential state.

By translating the requirements into a clean loop, the logic stays easy to reason about.

Approach

Iterate through the data once, updating the state needed to compute the answer.

Return the final state after the traversal is complete.

Steps:

  • Parse the input.
  • Iterate and update state.
  • Return the computed answer.

Example

Input: n = 10, logs = [[0,3],[2,5],[0,9],[1,15]] Output: 1 Explanation: Task 0 started at 0 and ended at 3 with 3 units of times. Task 1 started at 3 and ended at 5 with 2 units of times. Task 2 started at 5 and ended at 9 with 4 units of times. Task 3 started at 9 and ended at 15 with 6 units of times. The task with the longest time is task 3 and the employee with id 1 is the one that worked on it, so we return 1.

Python Solution

class Solution: def hardestWorker(self, n: int, logs: List[List[int]]) -> int: last = mx = ans = 0 for uid, t in logs: t -= last if mx < t or (mx == t and ans > uid): ans, mx = uid, t last += t return ans

Complexity

The time complexity is O(n)O(n)O(n), where nnn is the length of the array logslogslogs. The space complexity is O(1)O(1)O(1).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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