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Leetcode #239: Sliding Window Maximum

In this guide, we solve Leetcode #239 Sliding Window Maximum in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given an array of integers nums, there is a sliding window of size k which is moving from the very left of the array to the very right. You can only see the k numbers in the window.

Quick Facts

  • Difficulty: Hard
  • Premium: No
  • Tags: Queue, Array, Sliding Window, Monotonic Queue, Heap (Priority Queue)

Intuition

We are looking for a contiguous region that satisfies a constraint, which is a classic sliding-window signal.

Expanding and shrinking the window lets us maintain validity without restarting the scan.

Approach

Grow the window with a right pointer, and shrink from the left only when the constraint is violated.

Track the best window as you go to keep the solution linear.

Steps:

  • Expand the right end of the window.
  • While invalid, move the left end to restore constraints.
  • Update the best window found.

Example

Input: nums = [1,3,-1,-3,5,3,6,7], k = 3 Output: [3,3,5,5,6,7] Explanation: Window position Max --------------- ----- [1 3 -1] -3 5 3 6 7 3 1 [3 -1 -3] 5 3 6 7 3 1 3 [-1 -3 5] 3 6 7 5 1 3 -1 [-3 5 3] 6 7 5 1 3 -1 -3 [5 3 6] 7 6 1 3 -1 -3 5 [3 6 7] 7

Python Solution

class Solution: def maxSlidingWindow(self, nums: List[int], k: int) -> List[int]: q = [(-v, i) for i, v in enumerate(nums[: k - 1])] heapify(q) ans = [] for i in range(k - 1, len(nums)): heappush(q, (-nums[i], i)) while q[0][1] <= i - k: heappop(q) ans.append(-q[0][0]) return ans

Complexity

The time complexity is O(n×log⁡k)O(n \times \log k)O(n×logk), and the space complexity is O(k)O(k)O(k). The space complexity is O(k)O(k)O(k).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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