Compute the Rank as a Percentage — LeetCode 2346 Python Solution
MediumLeetCode PremiumDatabase
- Problem
- #2346
- Reading time
- 4 min
- Source
- leetcode.com
Table schema
SQL
Table: Students +---------------+------+ | Column Name | Type | +---------------+------+ | student_id | int | | department_id | int | | mark | int | +---------------+------+ student_id contains unique values. Each row of this table indicates a student's ID, the ID of the department in which the student enrolled, and their mark in the exam.Example
SQL
+---------------+------+
| Column Name | Type |
+---------------+------+
| student_id | int |
| department_id | int |
| mark | int |
+---------------+------+
student_id contains unique values.
Each row of this table indicates a student's ID, the ID of the department in which the student enrolled, and their mark in the exam.Python solution
Python
import duckdb
import pandas as pd
def solution(students: pd.DataFrame) -> pd.DataFrame:
con = duckdb.connect()
con.register("Students", students)
return con.execute("""SELECT
student_id,
department_id,
IFNULL(
ROUND(
(
RANK() OVER (
PARTITION BY department_id
ORDER BY mark DESC
) - 1
) * 100 / (COUNT(1) OVER (PARTITION BY department_id) - 1),
2
),
0
) AS percentage
FROM Students;""").df()Complexity
| Measure | Complexity |
|---|---|
| Time | O(n log n) (typical) |
| Space | O(n) auxiliary |
Related problems
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