Valid Palindrome IV — LeetCode 2330 Python Solution

MediumLeetCode PremiumTwo PointersString
Problem
#2330
Reading time
2 min

The problem

You are given a 0-indexed string s consisting of only lowercase English letters. In one operation, you can change any character of s to any other character.

Example

Input
s = "abcdba"
Output
true
Explanation
One way to make s a palindrome using 1 operation is:

Python solution

Python
class Solution:
    def makePalindrome(self, s: str) -> bool:
        i, j = 0, len(s) - 1
        cnt = 0
        while i < j:
            cnt += s[i] != s[j]
            i, j = i + 1, j - 1
        return cnt <= 2

Complexity

MeasureComplexity
TimeO(n)
SpaceO(1) auxiliary

Pattern: Two Pointers

Use the order already in the input to discard half the search space at every step. LeetCode 2330. Valid Palindrome IV is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Two Pointers.

The two pointers guide has the Python template for the pattern and the 201 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 2330. Valid Palindrome IV?
LeetCode 2330. Valid Palindrome IV is rated Medium on LeetCode.
What is the time complexity of LeetCode 2330. Valid Palindrome IV?
The Python solution on this page runs in O(n).
What is the space complexity of LeetCode 2330. Valid Palindrome IV?
The Python solution on this page uses O(1) auxiliary space.
What topics does LeetCode 2330. Valid Palindrome IV cover?
LeetCode 2330. Valid Palindrome IV is tagged Two Pointers and String on LeetCode.
Is LeetCode 2330. Valid Palindrome IV a premium problem?
Yes. LeetCode 2330. Valid Palindrome IV is a LeetCode Premium problem, so the full statement and test cases require a paid LeetCode subscription.

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