Stealth Interview
  • Features
  • Pricing
  • Blog
  • Login
  • Sign up

Leetcode #2305: Fair Distribution of Cookies

In this guide, we solve Leetcode #2305 Fair Distribution of Cookies in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given an integer array cookies, where cookies[i] denotes the number of cookies in the ith bag. You are also given an integer k that denotes the number of children to distribute all the bags of cookies to.

Quick Facts

  • Difficulty: Medium
  • Premium: No
  • Tags: Bit Manipulation, Array, Dynamic Programming, Backtracking, Bitmask

Intuition

The problem breaks into overlapping subproblems, so caching results prevents exponential repetition.

A carefully chosen DP state captures exactly what we need to build the final answer.

Approach

Define the DP state and recurrence, then compute states in the correct order.

Optionally compress space once the recurrence is clear.

Steps:

  • Choose a DP state definition.
  • Write the recurrence and base cases.
  • Compute states in the correct order.

Example

Input: cookies = [8,15,10,20,8], k = 2 Output: 31 Explanation: One optimal distribution is [8,15,8] and [10,20] - The 1st child receives [8,15,8] which has a total of 8 + 15 + 8 = 31 cookies. - The 2nd child receives [10,20] which has a total of 10 + 20 = 30 cookies. The unfairness of the distribution is max(31,30) = 31. It can be shown that there is no distribution with an unfairness less than 31.

Python Solution

class Solution: def distributeCookies(self, cookies: List[int], k: int) -> int: def dfs(i): if i >= len(cookies): nonlocal ans ans = max(cnt) return for j in range(k): if cnt[j] + cookies[i] >= ans or (j and cnt[j] == cnt[j - 1]): continue cnt[j] += cookies[i] dfs(i + 1) cnt[j] -= cookies[i] ans = inf cnt = [0] * k cookies.sort(reverse=True) dfs(0) return ans

Complexity

The time complexity is O(n·m) (typical). The space complexity is O(n·m) or optimized.

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


Ace your next coding interview

We're here to help you ace your next coding interview.

Subscribe
Stealth Interview
© 2026 Stealth Interview®Stealth Interview is a registered trademark. All rights reserved.
Product
  • Blog
  • Pricing
Company
  • Terms of Service
  • Privacy Policy