How hard is LeetCode 2305. Fair Distribution of Cookies?

LeetCode 2305. Fair Distribution of Cookies is rated Medium on LeetCode.

What topics does LeetCode 2305. Fair Distribution of Cookies cover?

LeetCode 2305. Fair Distribution of Cookies is tagged Bit Manipulation, Array, Dynamic Programming, Backtracking and Bitmask on LeetCode.

MediumNo. 2305

Fair Distribution of Cookies — LeetCode 2305 Python Solution

Pattern: Backtracking
Topics: Bit Manipulation, Array, Dynamic Programming, Backtracking, Bitmask
Reading time: 4 min
Source: leetcode.com

The problem

You are given an integer array cookies, where cookies[i] denotes the number of cookies in the ith bag. You are also given an integer k that denotes the number of children to distribute all the bags of cookies to.

Example

Input: cookies = [8,15,10,20,8], k = 2
Output: 31
Explanation: One optimal distribution is [8,15,8] and [10,20]

Python solution

PythonSolution

class Solution:
    def distributeCookies(self, cookies: List[int], k: int) -> int:
        def dfs(i):
            if i >= len(cookies):
                nonlocal ans
                ans = max(cnt)
                return
            for j in range(k):
                if cnt[j] + cookies[i] >= ans or (j and cnt[j] == cnt[j - 1]):
                    continue
                cnt[j] += cookies[i]
                dfs(i + 1)
                cnt[j] -= cookies[i]

        ans = inf
        cnt = [0] * k
        cookies.sort(reverse=True)
        dfs(0)
        return ans

Complexity

Time: O(n·m) (typical)
Space · auxiliary: O(n·m)or optimized

Pattern: Backtracking

Build candidates one choice at a time and abandon a branch the moment it cannot work. LeetCode 2305. Fair Distribution of Cookies is filed here because LeetCode tags it Backtracking, which is the vocabulary this hub collects.

The backtracking guide has the Python template for the pattern and the 105 LeetCode problems that use it.

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Frequently asked questions

How hard is LeetCode 2305. Fair Distribution of Cookies?: LeetCode 2305. Fair Distribution of Cookies is rated Medium on LeetCode.
What topics does LeetCode 2305. Fair Distribution of Cookies cover?: LeetCode 2305. Fair Distribution of Cookies is tagged Bit Manipulation, Array, Dynamic Programming, Backtracking and Bitmask on LeetCode.

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python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

Technical interview · 45 minsolution.pyShared editor · Python 3Longest substring without repeatsMediumGiven a string s, return the length of the longest contiguous substring in which every character is unique.s = "abcabcbb"
→ 31def length_of_longest_substring(s: str) -> int:2 last_seen = {}3 left = best = 04 for right, ch in enumerate(s):5 if ch in last_seen and last_seen[ch] >= left:

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

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Transcribing...

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

Primary display

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

The problem

Example

Python solution

Complexity

Pattern: Backtracking

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