Strong Password Checker II — LeetCode 2299 Python Solution
EasyString
- Problem
- #2299
- Pattern
- Hash Map
- Reading time
- 3 min
- Source
- leetcode.com
The problem
A password is said to be strong if it satisfies all the following criteria: It has at least 8 characters. It contains at least one lowercase letter.
Example
- Input
- password = "IloveLe3tcode!"
- Output
- true
- Explanation
- The password meets all the requirements. Therefore, we return true.
Python solution
Python
class Solution:
def strongPasswordCheckerII(self, password: str) -> bool:
if len(password) < 8:
return False
mask = 0
for i, c in enumerate(password):
if i and c == password[i - 1]:
return False
if c.islower():
mask |= 1
elif c.isupper():
mask |= 2
elif c.isdigit():
mask |= 4
else:
mask |= 8
return mask == 15Complexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(1) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 2299. Strong Password Checker II is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 2299. Strong Password Checker II?
- LeetCode 2299. Strong Password Checker II is rated Easy on LeetCode.
- What is the time complexity of LeetCode 2299. Strong Password Checker II?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 2299. Strong Password Checker II?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 2299. Strong Password Checker II cover?
- LeetCode 2299. Strong Password Checker II is tagged String on LeetCode.