Stealth Interview
  • Features
  • Pricing
  • Blog
  • Login
  • Sign up

Leetcode #2187: Minimum Time to Complete Trips

In this guide, we solve Leetcode #2187 Minimum Time to Complete Trips in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given an array time where time[i] denotes the time taken by the ith bus to complete one trip. Each bus can make multiple trips successively; that is, the next trip can start immediately after completing the current trip.

Quick Facts

  • Difficulty: Medium
  • Premium: No
  • Tags: Array, Binary Search

Intuition

The problem structure suggests a monotonic decision, which makes binary search a natural fit.

By halving the search space each step, we reach the answer efficiently.

Approach

Search either directly on a sorted array or on the answer space using a check function.

Each check is fast, and the logarithmic search keeps the overall runtime low.

Steps:

  • Define the search bounds.
  • Check the mid point condition.
  • Narrow the bounds until convergence.

Example

Input: time = [1,2,3], totalTrips = 5 Output: 3 Explanation: - At time t = 1, the number of trips completed by each bus are [1,0,0]. The total number of trips completed is 1 + 0 + 0 = 1. - At time t = 2, the number of trips completed by each bus are [2,1,0]. The total number of trips completed is 2 + 1 + 0 = 3. - At time t = 3, the number of trips completed by each bus are [3,1,1]. The total number of trips completed is 3 + 1 + 1 = 5. So the minimum time needed for all buses to complete at least 5 trips is 3.

Python Solution

class Solution: def minimumTime(self, time: List[int], totalTrips: int) -> int: mx = min(time) * totalTrips return bisect_left( range(mx), totalTrips, key=lambda x: sum(x // v for v in time) )

Complexity

The time complexity is O(n×log⁡(m×k))O(n \times \log(m \times k))O(n×log(m×k)), where nnn and kkk are the length of the array timetimetime and totalTripstotalTripstotalTrips respectively, and mmm is the minimum value in the array timetimetime. The space complexity is O(1)O(1)O(1).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


Ace your next coding interview

We're here to help you ace your next coding interview.

Subscribe
Stealth Interview
© 2026 Stealth Interview®Stealth Interview is a registered trademark. All rights reserved.
Product
  • Blog
  • Pricing
Company
  • Terms of Service
  • Privacy Policy