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Leetcode #2175: The Change in Global Rankings

In this guide, we solve Leetcode #2175 The Change in Global Rankings in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

Table: TeamPoints +-------------+---------+ | Column Name | Type | +-------------+---------+ | team_id | int | | name | varchar | | points | int | +-------------+---------+ team_id contains unique values. Each row of this table contains the ID of a national team, the name of the country it represents, and the points it has in the global rankings.

Quick Facts

  • Difficulty: Medium
  • Premium: Yes
  • Tags: Database

Intuition

The task is relational in nature, which maps cleanly to DataFrame operations in Python.

By treating tables as DataFrames, joins and group-bys become concise and readable.

Approach

Load the inputs as DataFrames and apply the appropriate merge, filter, or group-by.

Select or rename the columns to match the required output.

Steps:

  • Load inputs as DataFrames.
  • Apply merge/groupby/filter operations.
  • Select the output columns.

Example

+-------------+---------+ | Column Name | Type | +-------------+---------+ | team_id | int | | name | varchar | | points | int | +-------------+---------+ team_id contains unique values. Each row of this table contains the ID of a national team, the name of the country it represents, and the points it has in the global rankings. No two teams will represent the same country.

Python Solution

import duckdb import pandas as pd def solution(team_points: pd.DataFrame, points_change: pd.DataFrame) -> pd.DataFrame: con = duckdb.connect() con.register("TeamPoints", team_points) con.register("PointsChange", points_change) return con.execute("""WITH P AS ( SELECT team_id, SUM(points_change) AS delta FROM PointsChange GROUP BY team_id ) SELECT team_id, name, CAST(RANK() OVER (ORDER BY points DESC, name) AS SIGNED) - CAST( RANK() OVER (ORDER BY (points + delta) DESC, name) AS SIGNED ) AS 'rank_diff' FROM TeamPoints JOIN P USING (team_id);""").df()

Complexity

The time complexity is O(n log n) (typical). The space complexity is O(n).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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