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Leetcode #2109: Adding Spaces to a String

In this guide, we solve Leetcode #2109 Adding Spaces to a String in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given a 0-indexed string s and a 0-indexed integer array spaces that describes the indices in the original string where spaces will be added. Each space should be inserted before the character at the given index.

Quick Facts

  • Difficulty: Medium
  • Premium: No
  • Tags: Array, Two Pointers, String, Simulation

Intuition

The constraints hint that we can reason about two ends of the data at once, which is perfect for a two-pointer scan.

Moving one pointer at a time keeps the invariant intact and avoids nested loops.

Approach

Place pointers at the left and right ends and move them based on the comparison or target condition.

This yields a clean linear pass after any required sorting.

Steps:

  • Set left and right pointers.
  • Move a pointer based on the condition.
  • Update the best answer while scanning.

Example

Input: s = "LeetcodeHelpsMeLearn", spaces = [8,13,15] Output: "Leetcode Helps Me Learn" Explanation: The indices 8, 13, and 15 correspond to the underlined characters in "LeetcodeHelpsMeLearn". We then place spaces before those characters.

Python Solution

class Solution: def addSpaces(self, s: str, spaces: List[int]) -> str: ans = [] j = 0 for i, c in enumerate(s): if j < len(spaces) and i == spaces[j]: ans.append(' ') j += 1 ans.append(c) return ''.join(ans)

Complexity

The time complexity is O(n+m)O(n + m)O(n+m), and the space complexity is O(n+m)O(n + m)O(n+m), where nnn and mmm are the lengths of the string sss and the array spacesspacesspaces, respectively. The space complexity is O(n+m)O(n + m)O(n+m), where nnn and mmm are the lengths of the string sss and the array spacesspacesspaces, respectively.

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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