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Leetcode #2095: Delete the Middle Node of a Linked List

In this guide, we solve Leetcode #2095 Delete the Middle Node of a Linked List in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

You are given the head of a linked list. Delete the middle node, and return the head of the modified linked list.

Quick Facts

  • Difficulty: Medium
  • Premium: No
  • Tags: Linked List, Two Pointers

Intuition

The constraints hint that we can reason about two ends of the data at once, which is perfect for a two-pointer scan.

Moving one pointer at a time keeps the invariant intact and avoids nested loops.

Approach

Place pointers at the left and right ends and move them based on the comparison or target condition.

This yields a clean linear pass after any required sorting.

Steps:

  • Set left and right pointers.
  • Move a pointer based on the condition.
  • Update the best answer while scanning.

Example

Input: head = [1,3,4,7,1,2,6] Output: [1,3,4,1,2,6] Explanation: The above figure represents the given linked list. The indices of the nodes are written below. Since n = 7, node 3 with value 7 is the middle node, which is marked in red. We return the new list after removing this node.

Python Solution

# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def deleteMiddle(self, head: Optional[ListNode]) -> Optional[ListNode]: dummy = ListNode(next=head) slow, fast = dummy, head while fast and fast.next: slow = slow.next fast = fast.next.next slow.next = slow.next.next return dummy.next

Complexity

The time complexity is O(n)O(n)O(n), where nnn is the length of the list. The space complexity is O(1)O(1)O(1).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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