How hard is LeetCode 1988. Find Cutoff Score for Each School?

LeetCode 1988. Find Cutoff Score for Each School is rated Medium on LeetCode.

What topics does LeetCode 1988. Find Cutoff Score for Each School cover?

LeetCode 1988. Find Cutoff Score for Each School is tagged Database on LeetCode.

Is LeetCode 1988. Find Cutoff Score for Each School a premium problem?

Yes. LeetCode 1988. Find Cutoff Score for Each School is a LeetCode Premium problem, so the full statement and test cases require a paid LeetCode subscription.

MediumNo. 1988LeetCode Premium

Find Cutoff Score for Each School — LeetCode 1988 Python Solution

Topics: Database
Reading time: 2 min
Source: leetcode.com

Table schema

SQLTable schema

Table: Schools +-------------+------+ | Column Name | Type | +-------------+------+ | school_id | int | | capacity | int | +-------------+------+ school_id is the column with unique values for this table. This table contains information about the capacity of some schools.

Example

SQLExample

+-------------+------+
| Column Name | Type |
+-------------+------+
| school_id   | int  |
| capacity    | int  |
+-------------+------+
school_id is the column with unique values for this table.
This table contains information about the capacity of some schools. The capacity is the maximum number of students the school can accept.

Python solution

PythonSolution

import duckdb
import pandas as pd

def solution(schools: pd.DataFrame, exam: pd.DataFrame) -> pd.DataFrame:
    con = duckdb.connect()
    con.register("Schools", schools)
    con.register("Exam", exam)
    return con.execute("""SELECT school_id, MIN(IFNULL(score, -1)) AS score
FROM
    Schools AS s
    LEFT JOIN Exam AS e ON s.capacity >= e.student_count
GROUP BY school_id;""").df()

Complexity

Time: O(n log n)(typical)
Space · auxiliary: O(n)

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Frequently asked questions

How hard is LeetCode 1988. Find Cutoff Score for Each School?: LeetCode 1988. Find Cutoff Score for Each School is rated Medium on LeetCode.
What topics does LeetCode 1988. Find Cutoff Score for Each School cover?: LeetCode 1988. Find Cutoff Score for Each School is tagged Database on LeetCode.
Is LeetCode 1988. Find Cutoff Score for Each School a premium problem?: Yes. LeetCode 1988. Find Cutoff Score for Each School is a LeetCode Premium problem, so the full statement and test cases require a paid LeetCode subscription.

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python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

Technical interview · 45 minsolution.pyShared editor · Python 3Longest substring without repeatsMediumGiven a string s, return the length of the longest contiguous substring in which every character is unique.s = "abcabcbb"
→ 31def length_of_longest_substring(s: str) -> int:2 last_seen = {}3 left = best = 04 for right, ch in enumerate(s):5 if ch in last_seen and last_seen[ch] >= left:

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 Terra

Transcribing...

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

90%Subscription

python

Please analyze this context and help me answer the question or solve the problem.

Transcript

"Okay, next one. Given a string, return the length of the longest substring that has no repeating characters. Walk me through your approach before you code it."

python

def length_of_longest_substring(s: str) -> int:    last_seen = {}                    # char -> index    left = best = 0    for right, ch in enumerate(s):        if ch in last_seen and last_seen[ch] >= left:            left = last_seen[ch] + 1  # jump past it        last_seen[ch] = right        best = max(best, right - left + 1)    return best    last_seen = {}                    # char -> index

Approach

At each index r, the window's left edge is:

left r = max (left r -1, last[s r] + 1)

Time O(n): each character enters and leaves the window once.
Space O(min(n, k)): k is the size of the character set.

Type your message...

GPT-6.1 TerraClear chat

Transcribing...

Primary display

QuitEscHide+QCapture+PCrop+OSubmit+EnterPress to get answerLeft/Right+Up/Down+

Table schema

Example

Python solution

Complexity

Related problems

Frequently asked questions

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Approach

Approach

Approach