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Leetcode #1966: Binary Searchable Numbers in an Unsorted Array

In this guide, we solve Leetcode #1966 Binary Searchable Numbers in an Unsorted Array in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

Consider a function that implements an algorithm similar to Binary Search. The function has two input parameters: sequence is a sequence of integers, and target is an integer value.

Quick Facts

  • Difficulty: Medium
  • Premium: Yes
  • Tags: Array, Binary Search

Intuition

The problem structure suggests a monotonic decision, which makes binary search a natural fit.

By halving the search space each step, we reach the answer efficiently.

Approach

Search either directly on a sorted array or on the answer space using a check function.

Each check is fast, and the logarithmic search keeps the overall runtime low.

Steps:

  • Define the search bounds.
  • Check the mid point condition.
  • Narrow the bounds until convergence.

Example

func(sequence, target) while sequence is not empty randomly choose an element from sequence as the pivot if pivot = target, return true else if pivot < target, remove pivot and all elements to its left from the sequence else, remove pivot and all elements to its right from the sequence end while return false

Python Solution

class Solution: def binarySearchableNumbers(self, nums: List[int]) -> int: n = len(nums) ok = [1] * n mx, mi = -1000000, 1000000 for i, x in enumerate(nums): if x < mx: ok[i] = 0 else: mx = x for i in range(n - 1, -1, -1): if nums[i] > mi: ok[i] = 0 else: mi = nums[i] return sum(ok)

Complexity

The time complexity is O(log n) or O(n log n). The space complexity is O(1).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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