Number of Visible People in a Queue — LeetCode 1944 Python Solution
HardStackArrayMonotonic Stack
- Problem
- #1944
- Pattern
- Stack
- Reading time
- 3 min
- Source
- leetcode.com
The problem
There are n people standing in a queue, and they numbered from 0 to n - 1 in left to right order. You are given an array heights of distinct integers where heights[i] represents the height of the ith person.
Example
- Input
- heights = [10,6,8,5,11,9]
- Output
- [3,1,2,1,1,0]
- Explanation
- Person 0 can see person 1, 2, and 4.
Python solution
Python
class Solution:
def canSeePersonsCount(self, heights: List[int]) -> List[int]:
n = len(heights)
ans = [0] * n
stk = []
for i in range(n - 1, -1, -1):
while stk and stk[-1] < heights[i]:
ans[i] += 1
stk.pop()
if stk:
ans[i] += 1
stk.append(heights[i])
return ansComplexity
| Measure | Complexity |
|---|---|
| Time | O(n) |
| Space | O(n) auxiliary |
Pattern: Stack
When the most recent unresolved thing is the one that matters, use a stack. LeetCode 1944. Number of Visible People in a Queue is filed here because LeetCode tags it Stack, which is the vocabulary this hub collects.
The stack guide has the Python template for the pattern and the 194 LeetCode problems that use it.
Related problems
Frequently asked questions
- How hard is LeetCode 1944. Number of Visible People in a Queue?
- LeetCode 1944. Number of Visible People in a Queue is rated Hard on LeetCode.
- What is the time complexity of LeetCode 1944. Number of Visible People in a Queue?
- The Python solution on this page runs in O(n).
- What is the space complexity of LeetCode 1944. Number of Visible People in a Queue?
- The Python solution on this page uses O(n) auxiliary space.
- What topics does LeetCode 1944. Number of Visible People in a Queue cover?
- LeetCode 1944. Number of Visible People in a Queue is tagged Stack, Array and Monotonic Stack on LeetCode.