Number of Visible People in a Queue — LeetCode 1944 Python Solution

HardStackArrayMonotonic Stack
Problem
#1944
Pattern
Stack
Reading time
3 min

The problem

There are n people standing in a queue, and they numbered from 0 to n - 1 in left to right order. You are given an array heights of distinct integers where heights[i] represents the height of the ith person.

Example

Input
heights = [10,6,8,5,11,9]
Output
[3,1,2,1,1,0]
Explanation
Person 0 can see person 1, 2, and 4.

Python solution

Python
class Solution:
    def canSeePersonsCount(self, heights: List[int]) -> List[int]:
        n = len(heights)
        ans = [0] * n
        stk = []
        for i in range(n - 1, -1, -1):
            while stk and stk[-1] < heights[i]:
                ans[i] += 1
                stk.pop()
            if stk:
                ans[i] += 1
            stk.append(heights[i])
        return ans

Complexity

MeasureComplexity
TimeO(n)
SpaceO(n) auxiliary

Pattern: Stack

When the most recent unresolved thing is the one that matters, use a stack. LeetCode 1944. Number of Visible People in a Queue is filed here because LeetCode tags it Stack, which is the vocabulary this hub collects.

The stack guide has the Python template for the pattern and the 194 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 1944. Number of Visible People in a Queue?
LeetCode 1944. Number of Visible People in a Queue is rated Hard on LeetCode.
What is the time complexity of LeetCode 1944. Number of Visible People in a Queue?
The Python solution on this page runs in O(n).
What is the space complexity of LeetCode 1944. Number of Visible People in a Queue?
The Python solution on this page uses O(n) auxiliary space.
What topics does LeetCode 1944. Number of Visible People in a Queue cover?
LeetCode 1944. Number of Visible People in a Queue is tagged Stack, Array and Monotonic Stack on LeetCode.

Stuck on problems like this in a live interview?

Stealth Interview is a desktop app for macOS and Windows. It reads the problem off your screen and returns a working solution with a step-by-step explanation and its time and space complexity — invisible to screen sharing.

Get Stealth Interview