Eliminate Maximum Number of Monsters — LeetCode 1921 Python Solution

MediumGreedyArraySorting
Problem
#1921
Pattern
Greedy
Reading time
2 min

The problem

You are playing a video game where you are defending your city from a group of n monsters. You are given a 0-indexed integer array dist of size n, where dist[i] is the initial distance in kilometers of the ith monster from the city.

Example

Input
dist = [1,3,4], speed = [1,1,1]
Output
3
Explanation
In the beginning, the distances of the monsters are [1,3,4]. You eliminate the first monster.

Python solution

Python
class Solution:
    def eliminateMaximum(self, dist: List[int], speed: List[int]) -> int:
        times = sorted((d - 1) // s for d, s in zip(dist, speed))
        for i, t in enumerate(times):
            if t < i:
                return i
        return len(times)

Complexity

MeasureComplexity
TimeO(n \times \log n)
SpaceO(n) auxiliary

Pattern: Greedy

Take the locally best option every time — when you can prove that never costs you later. LeetCode 1921. Eliminate Maximum Number of Monsters is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Greedy.

The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 1921. Eliminate Maximum Number of Monsters?
LeetCode 1921. Eliminate Maximum Number of Monsters is rated Medium on LeetCode.
What is the time complexity of LeetCode 1921. Eliminate Maximum Number of Monsters?
The Python solution on this page runs in O(n \times \log n).
What is the space complexity of LeetCode 1921. Eliminate Maximum Number of Monsters?
The Python solution on this page uses O(n) auxiliary space.
What topics does LeetCode 1921. Eliminate Maximum Number of Monsters cover?
LeetCode 1921. Eliminate Maximum Number of Monsters is tagged Greedy, Array and Sorting on LeetCode.

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