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Leetcode #1908: Game of Nim

In this guide, we solve Leetcode #1908 Game of Nim in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

Alice and Bob take turns playing a game with Alice starting first. In this game, there are n piles of stones.

Quick Facts

  • Difficulty: Medium
  • Premium: Yes
  • Tags: Bit Manipulation, Brainteaser, Array, Math, Dynamic Programming, Game Theory

Intuition

The problem breaks into overlapping subproblems, so caching results prevents exponential repetition.

A carefully chosen DP state captures exactly what we need to build the final answer.

Approach

Define the DP state and recurrence, then compute states in the correct order.

Optionally compress space once the recurrence is clear.

Steps:

  • Choose a DP state definition.
  • Write the recurrence and base cases.
  • Compute states in the correct order.

Example

Input: piles = [1] Output: true Explanation: There is only one possible scenario: - On the first turn, Alice removes one stone from the first pile. piles = [0]. - On the second turn, there are no stones left for Bob to remove. Alice wins.

Python Solution

class Solution: def nimGame(self, piles: List[int]) -> bool: @cache def dfs(st): lst = list(st) for i, x in enumerate(lst): for j in range(1, x + 1): lst[i] -= j if not dfs(tuple(lst)): return True lst[i] += j return False return dfs(tuple(piles))

Complexity

The time complexity is O(n·m) (typical). The space complexity is O(n·m) or optimized.

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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