HardNo. 1896
Minimum Cost to Change the Final Value of Expression — LeetCode 1896 Python Solution
- Pattern
- Stack
- Topics
- Stack, Math, String, Dynamic Programming
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given a valid boolean expression as a string expression consisting of the characters '1','0','&' (bitwise AND operator),'|' (bitwise OR operator),'(', and ')'. For example, "()1|1" and "(1)&()" are not valid while "1", "(((1))|(0))", and "1|(0&(1))" are valid expressions.
Example
- Input
- expression = "1&(0|1)"
- Output
- 1
- Explanation
- We can turn "1&(0|1)" into "1&(0&1)" by changing the '|' to a '&' using 1 operation.
Complexity
- Time
- O(n·m) (typical)
- Space · auxiliary
- O(n·m)or optimized
Pattern: Stack
When the most recent unresolved thing is the one that matters, use a stack. LeetCode 1896. Minimum Cost to Change the Final Value of Expression is filed here because LeetCode tags it Stack, which is the vocabulary this hub collects.
The stack guide has the Python template for the pattern and the 194 LeetCode problems that use it.
Related problems
| No. | Problem | Difficulty |
|---|---|---|
| 0032 | Longest Valid Parentheses | Hard |
| 0241 | Different Ways to Add Parentheses | Medium |
| 0488 | Zuma Game | Hard |
| 0678 | Valid Parenthesis String | Medium |
| 1653 | Minimum Deletions to Make String Balanced | Medium |
| 2063 | Vowels of All Substrings | Medium |
Frequently asked questions
- How hard is LeetCode 1896. Minimum Cost to Change the Final Value of Expression?
LeetCode 1896. Minimum Cost to Change the Final Value of Expression is rated Hard on LeetCode.
- What topics does LeetCode 1896. Minimum Cost to Change the Final Value of Expression cover?
LeetCode 1896. Minimum Cost to Change the Final Value of Expression is tagged Stack, Math, String and Dynamic Programming on LeetCode.