MediumNo. 1874LeetCode Premium
Minimize Product Sum of Two Arrays — LeetCode 1874 Python Solution
- Pattern
- Greedy
- Topics
- Greedy, Array, Sorting
- Reading time
- 2 min
- Source
- leetcode.com
The problem
The product sum of two equal-length arrays a and b is equal to the sum of a[i] * b[i] for all 0 <= i < a.length (0-indexed). For example, if a = [1,2,3,4] and b = [5,2,3,1], the product sum would be 1*5 + 2*2 + 3*3 + 4*1 = 22.
Example
- Input
- nums1 = [5,3,4,2], nums2 = [4,2,2,5]
- Output
- 40
- Explanation
- We can rearrange nums1 to become [3,5,4,2]. The product sum of [3,5,4,2] and [4,2,2,5] is 3*4 + 5*2 + 4*2 + 2*5 = 40.
Python solution
class Solution:
def minProductSum(self, nums1: List[int], nums2: List[int]) -> int:
nums1.sort()
nums2.sort(reverse=True)
return sum(x * y for x, y in zip(nums1, nums2))Complexity
- Time
- O(n × log n)
- Space · auxiliary
- O(log n)
Pattern: Greedy
Take the locally best option every time — when you can prove that never costs you later. LeetCode 1874. Minimize Product Sum of Two Arrays is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Greedy.
The greedy guide has the Python template for the pattern and the 346 LeetCode problems that use it.
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Frequently asked questions
- How hard is LeetCode 1874. Minimize Product Sum of Two Arrays?
LeetCode 1874. Minimize Product Sum of Two Arrays is rated Medium on LeetCode.
- What is the time complexity of LeetCode 1874. Minimize Product Sum of Two Arrays?
The Python solution on this page runs in O(n × log n).
- What is the space complexity of LeetCode 1874. Minimize Product Sum of Two Arrays?
The Python solution on this page uses O(log n) auxiliary space.
- What topics does LeetCode 1874. Minimize Product Sum of Two Arrays cover?
LeetCode 1874. Minimize Product Sum of Two Arrays is tagged Greedy, Array and Sorting on LeetCode.
- Is LeetCode 1874. Minimize Product Sum of Two Arrays a premium problem?
Yes. LeetCode 1874. Minimize Product Sum of Two Arrays is a LeetCode Premium problem, so the full statement and test cases require a paid LeetCode subscription.