Replace All Digits with Characters — LeetCode 1844 Python Solution

EasyString
Problem
#1844
Pattern
Hash Map
Reading time
2 min

The problem

You are given a 0-indexed string s that has lowercase English letters in its even indices and digits in its odd indices. You must perform an operation shift(c, x), where c is a character and x is a digit, that returns the xth character after c.

Example

Input
s = "a1c1e1"
Output
"abcdef"
Explanation
The digits are replaced as follows:

Python solution

Python
class Solution:
    def replaceDigits(self, s: str) -> str:
        s = list(s)
        for i in range(1, len(s), 2):
            s[i] = chr(ord(s[i - 1]) + int(s[i]))
        return ''.join(s)

Complexity

MeasureComplexity
TimeO(n), where n is the length of the string s
SpaceO(1) auxiliary

Pattern: Hash Map

Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1844. Replace All Digits with Characters is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.

The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.

Related problems

Frequently asked questions

How hard is LeetCode 1844. Replace All Digits with Characters?
LeetCode 1844. Replace All Digits with Characters is rated Easy on LeetCode.
What is the time complexity of LeetCode 1844. Replace All Digits with Characters?
The Python solution on this page runs in O(n), where n is the length of the string s.
What is the space complexity of LeetCode 1844. Replace All Digits with Characters?
The Python solution on this page uses O(1) auxiliary space.
What topics does LeetCode 1844. Replace All Digits with Characters cover?
LeetCode 1844. Replace All Digits with Characters is tagged String on LeetCode.

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