Replace All Digits with Characters — LeetCode 1844 Python Solution
- Problem
- #1844
- Pattern
- Hash Map
- Reading time
- 2 min
- Source
- leetcode.com
The problem
You are given a 0-indexed string s that has lowercase English letters in its even indices and digits in its odd indices. You must perform an operation shift(c, x), where c is a character and x is a digit, that returns the xth character after c.
Example
- Input
- s = "a1c1e1"
- Output
- "abcdef"
- Explanation
- The digits are replaced as follows:
Python solution
class Solution:
def replaceDigits(self, s: str) -> str:
s = list(s)
for i in range(1, len(s), 2):
s[i] = chr(ord(s[i - 1]) + int(s[i]))
return ''.join(s)Complexity
| Measure | Complexity |
|---|---|
| Time | O(n), where n is the length of the string s |
| Space | O(1) auxiliary |
Pattern: Hash Map
Trade memory for time: remember what you have seen so the second pass never happens. LeetCode 1844. Replace All Digits with Characters is filed here because the reference solution below belongs to the algorithm family this hub collects, even though its LeetCode tags point elsewhere.
The hash map guide has the Python template for the pattern and the 709 LeetCode problems that use it.
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Frequently asked questions
- How hard is LeetCode 1844. Replace All Digits with Characters?
- LeetCode 1844. Replace All Digits with Characters is rated Easy on LeetCode.
- What is the time complexity of LeetCode 1844. Replace All Digits with Characters?
- The Python solution on this page runs in O(n), where n is the length of the string s.
- What is the space complexity of LeetCode 1844. Replace All Digits with Characters?
- The Python solution on this page uses O(1) auxiliary space.
- What topics does LeetCode 1844. Replace All Digits with Characters cover?
- LeetCode 1844. Replace All Digits with Characters is tagged String on LeetCode.