MediumNo. 1551

Minimum Operations to Make Array Equal — LeetCode 1551 Python Solution

Topics
Math
Reading time
2 min

The problem

You have an array arr of length n where arr[i] = (2 * i) + 1 for all valid values of i (i.e., 0 <= i < n). In one operation, you can select two indices x and y where 0 <= x, y < n and subtract 1 from arr[x] and add 1 to arr[y] (i.e., perform arr[x] -=1 and arr[y] += 1).

Example

Input
n = 3
Output
2
Explanation
arr = [1, 3, 5]

Python solution

PythonSolution
class Solution:
    def minOperations(self, n: int) -> int:
        return sum(n - (i << 1 | 1) for i in range(n >> 1))

Complexity

Time
O(n)where n is the length of the array
Space · auxiliary
O(1)

Pattern: Math and Number Theory

Find the closed form, the invariant, or the modular identity — and skip the loop entirely. LeetCode 1551. Minimum Operations to Make Array Equal is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Math.

The math and number theory guide has the Python template for the pattern and the 485 LeetCode problems that use it.

Related problems

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2541Minimum Operations to Make Array Equal IIMedium
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Frequently asked questions

How hard is LeetCode 1551. Minimum Operations to Make Array Equal?

LeetCode 1551. Minimum Operations to Make Array Equal is rated Medium on LeetCode.

What is the time complexity of LeetCode 1551. Minimum Operations to Make Array Equal?

The Python solution on this page runs in O(n), where n is the length of the array.

What is the space complexity of LeetCode 1551. Minimum Operations to Make Array Equal?

The Python solution on this page uses O(1) auxiliary space.

What topics does LeetCode 1551. Minimum Operations to Make Array Equal cover?

LeetCode 1551. Minimum Operations to Make Array Equal is tagged Math on LeetCode.

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