EasyNo. 1486

XOR Operation in an Array — LeetCode 1486 Python Solution

Topics
Bit Manipulation, Math
Reading time
2 min

The problem

You are given an integer n and an integer start. Define an array nums where nums[i] = start + 2 * i (0-indexed) and n == nums.length.

Example

Input
n = 5, start = 0
Output
8
Explanation
Array nums is equal to [0, 2, 4, 6, 8] where (0 ^ 2 ^ 4 ^ 6 ^ 8) = 8.

Python solution

PythonSolution
class Solution:
    def xorOperation(self, n: int, start: int) -> int:
        return reduce(xor, ((start + 2 * i) for i in range(n)))

Complexity

Time
O(n)where n is the length of the array
Space · auxiliary
O(1)

Pattern: Bit Manipulation

Use XOR, masks and the low-bit trick to replace whole data structures with an integer. LeetCode 1486. XOR Operation in an Array is filed here on both counts: the reference solution below belongs to the algorithm family this hub collects, and LeetCode tags it Bit Manipulation.

The bit manipulation guide has the Python template for the pattern and the 194 LeetCode problems that use it.

Related problems

Related problems
No.ProblemDifficulty
0029Divide Two IntegersMedium
0067Add BinaryEasy
0231Power of TwoEasy
0342Power of FourEasy
0371Sum of Two IntegersMedium
0405Convert a Number to HexadecimalEasy

Frequently asked questions

How hard is LeetCode 1486. XOR Operation in an Array?

LeetCode 1486. XOR Operation in an Array is rated Easy on LeetCode.

What is the time complexity of LeetCode 1486. XOR Operation in an Array?

The Python solution on this page runs in O(n), where n is the length of the array.

What is the space complexity of LeetCode 1486. XOR Operation in an Array?

The Python solution on this page uses O(1) auxiliary space.

What topics does LeetCode 1486. XOR Operation in an Array cover?

LeetCode 1486. XOR Operation in an Array is tagged Bit Manipulation and Math on LeetCode.

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