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Leetcode #1431: Kids With the Greatest Number of Candies

In this guide, we solve Leetcode #1431 Kids With the Greatest Number of Candies in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

There are n kids with candies. You are given an integer array candies, where each candies[i] represents the number of candies the ith kid has, and an integer extraCandies, denoting the number of extra candies that you have.

Quick Facts

  • Difficulty: Easy
  • Premium: No
  • Tags: Array

Intuition

The constraints allow a direct scan that keeps only the essential state.

By translating the requirements into a clean loop, the logic stays easy to reason about.

Approach

Iterate through the data once, updating the state needed to compute the answer.

Return the final state after the traversal is complete.

Steps:

  • Parse the input.
  • Iterate and update state.
  • Return the computed answer.

Example

Input: candies = [2,3,5,1,3], extraCandies = 3 Output: [true,true,true,false,true] Explanation: If you give all extraCandies to: - Kid 1, they will have 2 + 3 = 5 candies, which is the greatest among the kids. - Kid 2, they will have 3 + 3 = 6 candies, which is the greatest among the kids. - Kid 3, they will have 5 + 3 = 8 candies, which is the greatest among the kids. - Kid 4, they will have 1 + 3 = 4 candies, which is not the greatest among the kids. - Kid 5, they will have 3 + 3 = 6 candies, which is the greatest among the kids.

Python Solution

class Solution: def kidsWithCandies(self, candies: List[int], extraCandies: int) -> List[bool]: mx = max(candies) return [candy + extraCandies >= mx for candy in candies]

Complexity

The time complexity is O(n). The space complexity is O(1) to O(n).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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