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Leetcode #1194: Tournament Winners

In this guide, we solve Leetcode #1194 Tournament Winners in Python and focus on the core idea that makes the solution efficient.

You will see the intuition, the step-by-step method, and a clean Python implementation you can use in interviews.

Leetcode

Problem Statement

Table: Players +-------------+-------+ | Column Name | Type | +-------------+-------+ | player_id | int | | group_id | int | +-------------+-------+ player_id is the primary key (column with unique values) of this table. Each row of this table indicates the group of each player.

Quick Facts

  • Difficulty: Hard
  • Premium: Yes
  • Tags: Database

Intuition

The task is relational in nature, which maps cleanly to DataFrame operations in Python.

By treating tables as DataFrames, joins and group-bys become concise and readable.

Approach

Load the inputs as DataFrames and apply the appropriate merge, filter, or group-by.

Select or rename the columns to match the required output.

Steps:

  • Load inputs as DataFrames.
  • Apply merge/groupby/filter operations.
  • Select the output columns.

Example

+-------------+-------+ | Column Name | Type | +-------------+-------+ | player_id | int | | group_id | int | +-------------+-------+ player_id is the primary key (column with unique values) of this table. Each row of this table indicates the group of each player.

Python Solution

import duckdb import pandas as pd def solution(players: pd.DataFrame, matches: pd.DataFrame) -> pd.DataFrame: con = duckdb.connect() con.register("Players", players) con.register("Matches", matches) return con.execute("""WITH s AS ( SELECT first_player AS player_id, first_score AS score, group_id FROM Matches AS m JOIN Players AS p ON m.first_player = p.player_id UNION ALL SELECT second_player AS player_id, second_score AS score, group_id FROM Matches AS m JOIN Players AS p ON m.second_player = p.player_id ), t AS ( SELECT group_id, player_id, SUM(score) AS scores FROM s GROUP BY player_id ), p AS ( SELECT group_id, player_id, RANK() OVER ( PARTITION BY group_id ORDER BY scores DESC, player_id ) AS rk FROM t ) SELECT group_id, player_id FROM p WHERE rk = 1;""").df()

Complexity

The time complexity is O(n log n) (typical). The space complexity is O(n).

Edge Cases and Pitfalls

Watch for boundary values, empty inputs, and duplicate values where applicable. If the problem involves ordering or constraints, confirm the invariant is preserved at every step.

Summary

This Python solution focuses on the essential structure of the problem and keeps the implementation interview-friendly while meeting the constraints.


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