User Purchase Platform — LeetCode 1127 Python Solution

HardLeetCode PremiumDatabase
Problem
#1127
Reading time
6 min

Table schema

SQL
Table: Spending +-------------+---------+ | Column Name | Type | +-------------+---------+ | user_id | int | | spend_date | date | | platform | enum | | amount | int | +-------------+---------+ The table logs the history of the spending of users that make purchases from an online shopping website that has a desktop and a mobile application. (user_id, spend_date, platform) is the primary key (combination of columns with unique values) of this table.

Example

SQL
+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| user_id     | int     |
| spend_date  | date    |
| platform    | enum    | 
| amount      | int     |
+-------------+---------+
The table logs the history of the spending of users that make purchases from an online shopping website that has a desktop and a mobile application.
(user_id, spend_date, platform) is the primary key (combination of columns with unique values) of this table.
The platform column is an ENUM (category) type of ('desktop', 'mobile').

Python solution

Python
import duckdb
import pandas as pd

def solution(spending: pd.DataFrame) -> pd.DataFrame:
    con = duckdb.connect()
    con.register("Spending", spending)
    return con.execute("""WITH
    P AS (
        SELECT DISTINCT spend_date, 'desktop' AS platform FROM Spending
        UNION
        SELECT DISTINCT spend_date, 'mobile' FROM Spending
        UNION
        SELECT DISTINCT spend_date, 'both' FROM Spending
    ),
    T AS (
        SELECT
            user_id,
            spend_date,
            SUM(amount) AS amount,
            IF(COUNT(platform) = 1, platform, 'both') AS platform
        FROM Spending
        GROUP BY 1, 2
    )
SELECT
    p.*,
    IFNULL(SUM(amount), 0) AS total_amount,
    COUNT(t.user_id) AS total_users
FROM
    P AS p
    LEFT JOIN T AS t USING (spend_date, platform)
GROUP BY 1, 2;""").df()

Complexity

MeasureComplexity
TimeO(n log n) (typical)
SpaceO(n) auxiliary

Related problems

Frequently asked questions

How hard is LeetCode 1127. User Purchase Platform?
LeetCode 1127. User Purchase Platform is rated Hard on LeetCode.
What topics does LeetCode 1127. User Purchase Platform cover?
LeetCode 1127. User Purchase Platform is tagged Database on LeetCode.
Is LeetCode 1127. User Purchase Platform a premium problem?
Yes. LeetCode 1127. User Purchase Platform is a LeetCode Premium problem, so the full statement and test cases require a paid LeetCode subscription.

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